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5v^2-31v=0
a = 5; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·5·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*5}=\frac{0}{10} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*5}=\frac{62}{10} =6+1/5 $
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